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Write the balanced equation for the reaction of aqueous Pb(ClO3)2 with aqueous NaI. Include phases.?

What mass of precipitate will form if 1.50 L of concentrated Pb(ClO3)2 is mixed with 0.100 L of 0.210 M NaI? Assume the reaction goes to completion.

I got the equation part, but you need the equation to do that so I figured I'd put it first. I got Pb(ClO3)2 (aq) + 2 NaI (aq) --> PbI2 (s) & 2 NaClO3 (aq)

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Pb(ClO3)2(aq) + 2 NaI(aq) → PbI2(s) + 2 NaClO3(aq)

(0.100 L) x (0.210 mol/L NaI) x (1 mol PbI2 / 2 mol NaI) x (461.0189 g PbI2/mol) = 4.84 g PbI2

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