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What magnetic field strength and direction will levitate the 1.9 g wire in the figure below, in which d = 13 cm?

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The magnetic force (I*L*B) must equal the weight (m*g)

So B = m*g/*I*L) = 0.0019kg*9.8m/s^2/(1.5A*0.13m) = 9.55x10^-2T and the field must be out of the page

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