Weight = 1100 * 9.8 = 10,780 N
The sum of the vertical components of the two tension forces is equal to the weight of the beam. The horizontal components of the two tension forces are equal in magnitude.
T1 * cos 20 + T2 * cos 30 = 10,780
T1 * sin 20 = T2 * sin 30
T1 = T2 * 2 * sin 20
T2 * 2 * sin 20 * cos 20 + T2 * cos 30 = 10,780
T2 = 10,780 ÷ (2 * sin 20 * cos 20 + cos 30)
This is approximately 7144.7 N.
T1 = [10,780 ÷ (2 * sin 20 * cos 20 + cos 30)] * 2 * sin 20
This is approximately 4,887 N.
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