if an object floats in water then the fraction of its volume that floats inside water is fiven by

d1/d1 ...where d1=density of the floating object and d2=density of water

hence fraction of volume of wood that floats inside water is given by

700/1000 (density of water=100 kg/m^3)

=0.7 part of volume floats inside water

hence 0.3 part of of vulme floats outside water

now volume of wood=10 *10*10=1000 cm^3 =10^-3 cubic metre

hence volume of wood outside water=0.3 *10^-3= 3*10^-4 cubic metre

height of block from water * base area =volume outside water

h*10 ^-2 metre sq.=3*10^-4 metre cube

h=3* 10^-2 m= 3 cm...this is the answer

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