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Complete this table of values for four aqueous solutions at 25 °C.?

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Solution A:

0.00011 M H+

(10^-14) / (0.00011) = 9.1 × 10^-11 M OH-

pH = - log 0.00011 = 4.0

pOH = 14 - pH = 14 - 4 = 10

Solution B:

0.000024 M OH-

(10^-14) / (0.000024) = 4.2 × 10^-10 M H+

pOH = - log 0.000024 = 4.6

pH = 14 - pOH = 9.4

Solution C:

pH = 8.06

pOH = 14 - pH = 5.94

(10^-8.06) = 8.7 × 10^-9 M H+

(10^-5.94) = 1.1 × 10^-6 M OH-

Solution D:

pOH =10.33

pH = 14 - pOH = 3.67

(10^-3.67) = 2.1 × 10^-4 M H+

(10^-10.33) = 4.7 × 10^-11 OH-

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