A 1200kg steel beam is supported by two ropes. What is the Tension of rope 1 and rope 2?

the picture of it is provided below. Where do i begin? Do i start with cos and sin? please help thank you

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A 1200kg steel beam is supported by two ropes. What is the Tension of rope 1 and rope 2?

the picture of it is provided below. Where do i begin? Do i start with cos and sin? please help thank you

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Let T1 = tension in rope 1 and T2 tension is rope 2.

Summation of forces along the y-axis = 0

T1y + T2y - W = 0

T1cos 20 + T2cos 30 - 1200kg(9.8 m/s^2) = 0

cos 20T1 + cos 30T2 = 11760 N eq. 1

Summation of forces along the x-axis = 0

T1x + T2x = 0

-T1sin20 + T2sin30 = 0

T2 = T1sin20/sin30

T2 = T1(0.68404) eq. 3

Substitute eq. 3 in eq. 1:

cos20T1 + cos30(T1(0.68404) = 11760 N

1.52309T1 = 11760 N

T1 = 11760 N/1.52309

T1 = 7721.1 N answer

T2 = (7721.1 N)(0.68404) = 5281.5 N answer

Hope this helps.

Summation of forces along the y-axis = 0

T1y + T2y - W = 0

T1cos 20 + T2cos 30 - 1200kg(9.8 m/s^2) = 0

cos 20T1 + cos 30T2 = 11760 N eq. 1

Summation of forces along the x-axis = 0

T1x + T2x = 0

-T1sin20 + T2sin30 = 0

T2 = T1sin20/sin30

T2 = T1(0.68404) eq. 3

Substitute eq. 3 in eq. 1:

cos20T1 + cos30(T1(0.68404) = 11760 N

1.52309T1 = 11760 N

T1 = 11760 N/1.52309

T1 = 7721.1 N answer

T2 = (7721.1 N)(0.68404) = 5281.5 N answer

Hope this helps.