# what is the potential difference vc−va?

It takes 2.5μJ of work to move a 16nC charge from point A to B. It takes -5.5μJ of work to move the charge from C to B.?

what is the potential difference vc−va?

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Vab = 2.5e-6/16e-9 = 156.25V <<<<

Vcb = -5.5e-6/16e-9 = -343.75 <<<<

Vab + Vbc = Vac

Vbc = - Vcb = 343.75

Vca = - Vac

Vca = -Vab -Vbc = -156.25-343.75 = -500V <<<<<

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Hello anonymous, So total work performed in moving 16 nC right from C to A is - 8.0 μJ

So energy required to move 1 C, by definition, the potential difference = - 8.0 * 10^-6 / 16 * 10^-9

So Vc - Va = -500 V

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