Immediately after the switch is closed, the capacitor has no voltage across it, and can be regarded as a short circuit.
R2 in parallel with R3 is 6*3/(6+3) ie 2 ohms.
The voltage across R2 is 42*2/(2+8) = 8.4
The current in R2 is 8.4/3 amps = 2.8 amps (B)
The current in R3 is 8.4/6 amps = 1.4 amps (C)
The current in R1 is the sum of those, ie, 4.2 amps (A)
When the capacitor is fully charged, it draws no current, and no volts are dropped across R3.
The voltage across the capacitor is 42*6/(6+8) = 18 volts
Charge is c*v = 72 uCoulombs (D)
Lorem ipsum dolor sit amet, consectetur adipiscing elit,
sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam,
quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. Duis aute irure dolor
in reprehenderit in voluptate velit esse cillum dolore eu fugiat.
SHOW ANSWER