Best Answer for A solution of benzoic acid (C6H5COOH) that is 0.20 M has a pH of 2.45. What is Ka for benzoic acid?
10^-2.45 = 0.00355 M (Concentration of H3O+ and the conjugate base)
[H3O+][A-]/[HA] = (0.00355^2)/(0.20 - 0.00355) = 6.4x10^-5
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