A

5.2/2=2.6 this is the time it take the foot ball to reach maximum height.

Calculate the distance it falls from it's maximum height. First write down all the values you know

initial velocity(Vi)=0 (no vertical motion at the top of it's maximum height, it "stops before it starts to fall downward.

a=9.8, this is due to gravity. t= 2.6 seconds. We want to find d, distance. Use a kinematic equation will these factors in it. In this case. d=Vit+0.5at^2

because Vi=0 Vit=0 therefor in this case d=0.5at^2

Substitute in the values. d=0.5x9.8x2.6^2=33.124m

You'll probably want to round this to 33m

B

You need to use the kinematic equations again for this one. Write down the factors you know, and the ones you want to find out.

For the motion, from being hit by the foot, to reaching maximum point.

a= -9.8 (gravity causing ball to decelerate that's why it's negative)

Vf=0

d=33m

t=2.6 seconds

Vi=? this is what we want to find.

this formula will word. Vf^2=Vi^2 +2ad

Vf=0 so Vf^2=0

rearrange to find Vi

Vi=Square rt of -2ad

Vi=Square rt of -2x-9.8x33

Vi=Square rt of 646.8

Vi=25.4 m/s

Good luck!

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