CuX = Cu2+ + X2-
Ksp = [Cu2+] * [X2-]
for each mole of CuX that dissolves we get x mol of each of the anions and cations
Ksp = x^2 = 1.27 x 10 ^-36
x= 1.13 x 10 ^-18 moles of CuX per liter of pure water
if the solution has [Cu2+]= 0.27 M
Ksp becomes x ( x + 0.27)
as we can see above x is extremely small so can be ignored inside the brackets
0.27 x = 1.27 x 10^-36
x = 1.27 x 10^-36 / 0.27 = 4.70 x 10 ^-36 moles per liter
In 0.19M X2- we have
Ksp = 0.19x = 1.27 x 10^-36
x = 1.27 x 10^-36 / 0.19 = 6.68 x 10 ^-36 moles per liter ..
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